## Magnetic force between a current loop and a wire

The Lorentz force (or electromagnetic force) is a mixture of electric and magnetic forces on a point charge caused by electromagnetic fields in physics (specifically in electromagnetism). A charge q particle moving at v in an electric field E and a magnetic field B is subjected to a force of (in SI units[1][2]). The electromagnetic force on a charge q is defined as a combination of a force in the direction of the electric field E, proportional to the magnitude of the field and the quantity of charge, and a force at right angles to the magnetic field B and the charge’s velocity v, proportional to the magnitude of the field, the charge, and the velocity. The magnetic force on a current-carrying wire (also known as the Laplace force), the electromotive force in a wire loop passing through a magnetic field (an element of Faraday’s law of induction), and the force on a moving charged particle are all defined by variations on this basic formula.
Historians believe the rule is implicit in a paper written by James Clerk Maxwell in 1865.
[three] In 1895, Hendrik Lorentz completed a full derivation,[4] defining the contribution of the electric force only a few years after Oliver Heaviside correctly identified the magnetic force’s contribution. (5)

## Find the net force exerted by the magnetic field due to the

A car goes around a vertical, circular circle at a constant speed in the loop-the-loop trip. The car weighs 230 kilograms and travels at a speed of 300 meters per second. R=20 m is the radius of the loop-the-loop. What is the magnitude of the usual force acting on the car as it moves up the side of the circle?
In other words, the centripetal acceleration towards the circle’s center is caused by the natural force from the rail. There are no other powers operating in the normal way, as far as I can tell. Keep in mind that you can only consider powers in the usual direction:
When an object moves in a vertical circle, the net force must be pointed towards the middle when it hits the side (west). This means that some other upward-directed force is counteracting the weight force. The explanation for this is that if the weight vector had no counteracting force, the resulting net force would not point towards the middle. To see this, draw the usual force supplied by the track towards the west and the weight vector towards the south at right angles from the point on the side.

### Wire and rectangular loop “smartphysics” solution.

Magnetic stress on current-carrying wires is most commonly used in motors. In a magnetic field, motors contain wire loops. The magnetic field exerts torque on the loops as current is passed through them, which rotates a shaft. In the phase, electrical energy is transformed into mechanical work. The direction of current is reversed until the loop’s surface area is aligned with the magnetic field, resulting in a constant torque on the loop ((Figure)). Commutators and brushes are used to reverse the current flow. To keep the motor moving, the commutator is set to reverse the current flow at predetermined points. There are three contact areas to avoid on a simple commutator, as well as dead spots where the loop will have zero instantaneous torque. During the spinning motion, the brushes rub against the commutator, causing electrical contact between sections of the commutator.
A dc electric motor in a simplified form. (a) A magnetic field is applied to the rectangular wire coil. According to the right-hand rule-1, the forces on the wires nearest to the magnetic poles (N and S) are in opposite directions. As a result of the net torque, the loop rotates to the location shown in (b). (b) The brushes have now come into contact with the commutator segments, preventing current from flowing through the loop. The loop is not subjected to any torque, but it tends to rotate at the initial velocity (a). As the loop is turned around, current flows through the wires in the opposite direction, and the phase repeats as before (a). The loop will continue to rotate as a result of this.

### 30 24

A long straight wire in Fig. 29-65 carries current i1 = 35.1 A, while a rectangular loop carries current i2 = 20.7 A. Take the following measurements: a = 0.977 cm, b = 9.84 cm, and L = 42.2 cm. What is the magnitude of the loop’s net force as a result of i1?
F/L = o I 1 I 2 /2r is the formula for force between two wires. Only parallel sections are affected by the force. The loop’s perpendicular parts will not be included. Since the current on the closer side of the loop is in the same direction as the force, the net force would be attractive.